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Conservation of Momentum

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Wrap-up

What you learned

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Key takeaway

  1. Momentum conservation applies to the whole isolated system. On the momentum graph, that means the total line stays flat even when the cart lines change.
  2. Internal forces come in equal-and-opposite pairs, so they give the carts equal-and-opposite momentum changes without changing the system total.

Common misconception

If two carts push on each other, one of them can win more of the system momentum by pushing harder or by having more mass.

Inside an isolated system, the force pair is equal and opposite, so the momentum changes are equal and opposite too. The system total does not have a winner.

  1. Momentum of one object

    One cart's momentum depends on both its mass and its velocity.

  2. Total momentum

    Add the cart momenta to get the system total. In this one-dimensional lab, the sign shows direction.

Why it behaves this way

Explanation

Conservation of momentum is about the total momentum of a system, not about each object keeping its own momentum. If no external impulse acts on the two-cart system, the sum of the carts' momenta stays constant even while they push or pull on one another internally.

In this module, two carts interact on one track during one internal-force window. Change the masses, system drift, force, or interaction time, then compare the stage with the force graph, momentum graph, and center-of-mass marker. The cart momenta can redistribute, but the system total and center-of-mass motion should stay consistent.

Key ideas

01Momentum conservation applies to the whole isolated system. On the momentum graph, that means the total line stays flat even when the cart lines change.
02Internal forces come in equal-and-opposite pairs, so they give the carts equal-and-opposite momentum changes without changing the system total.
03Equal momentum changes do not imply equal speed changes. The lighter cart usually changes speed more because .

Worked examples

Live conservation checks

Open examples when you want to see the same idea walked through step by step.

Frozen walkthrough

Step through the frozen example

Frozen walkthrough
Use the live stage and graphs as evidence. First compute the system total momentum at the instant shown. Then use the current interaction to predict the final momentum split and compare that prediction with the momentum bars, force graph, and center-of-mass motion.

Supporter unlocks saved study tools, exact-state sharing, and the richer review surfaces that support this guided flow.

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Example 1 of 2
Frozen valuesFrozen at 0.00

At , what is the system's total momentum?

Time

0 s

Momentum of cart A

0 kg m/s

Momentum of cart B

0 kg m/s

1. Write the system total

Use for the same instant shown on the stage.

2. Substitute the live momenta

.

3. Add them

So .

System total momentum

The total momentum is essentially zero here, so the center of mass stays at rest even while the carts separate.

Quick test

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Accessibility

Accessibility

Open the text-first descriptions when you need the simulation and graph translated into words.

The simulation shows two carts on one horizontal track with a fixed time window for an internal interaction. Each cart has a mass label, a velocity arrow, and optional force arrows that appear in equal and opposite directions during the interaction window.

Optional overlays can draw an isolated-system boundary around both carts, a center-of-mass marker, and centered momentum bars for cart A, cart B, and the system total. Changing the masses, system velocity, internal force, or interaction duration updates the carts, readouts, and linked graphs without changing the underlying track scale.

Graph summary

The force graph shows equal and opposite internal force lines during the interaction window plus a zero external-force baseline. The momentum graph shows the carts' individual momentum lines changing in opposite directions while the total line stays flat.

The velocity graph shows how the same momentum exchange can create different speed changes for different masses, while the center-of-mass speed stays constant for the whole isolated system.

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Progress

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